9=(8^2/2)+3(5z-15)-13z

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Solution for 9=(8^2/2)+3(5z-15)-13z equation: 



9=(8^2/2)+3(5z-15)-13z

We move all terms to the left:

9-((8^2/2)+3(5z-15)-13z)=0



Domain of the equation: 2)+3(5z-15)-13z)!=0

z∈R



We multiply all the terms by the denominator


-((8^2+9*2)+3(5z-15)-13z)=0



We calculate terms in parentheses: -((8^2+9*2)+3(5z-15)-13z), so:

(8^2+9*2)+3(5z-15)-13z

determiningTheFunctionDomain
3(5z-15)-13z+(8^2+9*2)

We add all the numbers together, and all the variables

-13z+3(5z-15)+82

We multiply parentheses

-13z+15z-45+82

We add all the numbers together, and all the variables

2z+37

Back to the equation:

-(2z+37)



We get rid of parentheses

-2z-37=0

We move all terms containing z to the left, all other terms to the right

-2z=37

z=37/-2

z=-18+1/2

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